Math, asked by mansoor62, 7 months ago

if cos=3/5 then what is the value of 6 tan°-5 cos°​

Answers

Answered by pushkart03
0

Answer:

cos = b/ h = 3/5

Step-by-step explanation:

using phytagoras theorem

h^2 = (p) ^2 + ( b) ^2

p^2 = (h)^2 - (b)^2

= (5)^2 - (3)^2

= 25 - 9 = 16

p^2 =16

p = √16 = 4

Now,

tan = p/b = 4/3

cos = b/h = 3/5

6 tan ° - 5 cos°

6 × 4/3 - 5 × 3/5

8 - 3 = 5

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