if cos 32 = x, determine in terms of x :
cos 64
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Answer:
The value of 32sin(
2
A
)sin(
2
5A
)
=16(cos2A−cos3A)
=16(2cos
2
A−1−4cos
3
A+3cosA)
=16(2×
16
9
−1−4×
64
27
+3×
4
3
)
=18−16+27+36=11
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