If cos(3A+B)=1/2 and sin(3A+B)=1/2 then find the value of tan3A+cot3A?
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Answered by
8
Explanation:
sin(3a-b) = 1/2
3a-b = 30…………….1
cos(3a+b) = 1/2
3a+b = 60……………2
Adding (1) and (2) we get a=15 and substituting value of a in any eqn we get b=15.
So tan3a=tan45 and cot3a =tan45
tan45 + cot45 = 1+1 =2
Hipe this helps you!!
Answered by
6
here is ur answer...thnkuh
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