if cos 3x=0 find the value of sins , cos2x
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0
this is right answer
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veer20:
cos0. =1
hw to solve 0
its ans is 1/2
ohh sorry
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3
i hope you understand very well
cos 3x=0=cos3×30
hence x=30°
sinx=sin30°=1/2
cos2×30=1/2=cos2x
cos 3x=0=cos3×30
hence x=30°
sinx=sin30°=1/2
cos2×30=1/2=cos2x
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nw hapy
smile nw
ok
can u solve one more
sec^2(90-x)-1/cot^2(90-x)=1
ya
we know sec90-x=cosecx
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