Question

if cos 43° = x/√x²+y² where x, y > 0, then the value of tan 47°= ?​

Answer 1

Answer:

give me best ans and thanks plzzzzz

Answer 2

Answer: tan 47°=$\frac{x}{y}$.

Step-by-step explanation:

Given:- cos 43° = $\frac{x}{\sqrt{x^{2} +y^{2} } }$

To find:- tan 47°= ?​

Concept:- Using a right angle triangle, we know cos is calculated by dividing base with hypotenuse. We calculate the perpendicular of the triangle.

Then one of the angle will be 47°.

Solution:-

Perpendicular=$\sqrt{(\sqrt{x^{2} +y^{2} })^{2} -x^{2} }$

                       = $\sqrt{y^{2} }$

                       = y.

The angle opposite to 43° will be 47°.

So, tan 47°=$\frac{x}{y}$.

• Hence, the required answer is $\frac{x}{y}$.

#SPJ3