Question

If cos 7A=sin(A-6°),where 7A is an acute angle,find the value of A.

Answer 1

Hey mate here is your answer.

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Explanation:

If cos 7A=sin(A-6°),where 7A is an acute angle,

find the value of A.

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Given,cos 7A=sin(A-6°),

⇒sin(90°-7A)=sin(A-6°),

Since,(90°-7A)and(A-6°) both are acute angles,

⇒90°-7A=A-6°,

⇒8A=96°°

⇒A=96/8,

A=12°.✔✔✔✔✔

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Hope it helps you.