Question

if cos(81+θ) = sin (k/3-θ) where θ is an acute angle, then the value of k is?

Answer 1

Answer:

hope this helps u

Step-by-step explanation:

cos (81+ theta ) = sin(k/3 - theta)

we know

cos theta = sin (90 - theta) for theta <= 90

so using this

cos(81 + theta) = sin (k/3- theta)

sin ( 90 - 81 - theta) = sin ( k/3 - theta)

sin( 9- theta) = sin (k/3 - theta)

comparing now angles

9- theta = k/3 - theta

k/3 = 9 -theta + theta

k/3 = 9

k= 9*3

k = 27