Question

if cos 9 alpha is equal to sin alpha and 9alpha less than 90degrees value of tan 5alpha

Answer 1

Answer:

hope this helps

Answer 2

Answer:

$\red {Value \:of \: tan 5\alpha }\pink {= 1}$

Step-by-step explanation:

$cos \:9\alpha = sin \alpha \: (Given)$

$\implies cos 9\alpha = cos ( 90 - \alpha )$

$\boxed {\pink { Since, sin \theta = cos (90 - \theta )}}$

$\implies 9\alpha = 90 - \alpha$

$\implies 9\alpha + \alpha = 90\degree$

$\implies 10\alpha = 90$

$\implies \alpha = \frac{90}{10} = 9\degree$

$Now , \: Value \:of : tan 5\alpha \\= tan ( 5\times 9) \\= tan 45\degree\\= 1$

Therefore.,

$\red { Value \:of \:tan \alpha }\green {= 1}$

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