Question

if cos (90-A)=0, the sin (A+B)=​

Answer 1

Answer:

$\boxed{ \boxed{ \huge{ \pink{sin \beta }}}}$

Step-by-step explanation:

$cos(90 - \alpha ) = 0 \\ cos(90 - \alpha ) = cos90 \\ 90 - \alpha = 90 \\ \alpha = 0 \\ sin( \alpha + \beta ) = sin(0 + \beta ) \\ \: \: \: \: \: \: \: \: \: \: \: = sin \beta$