Math, asked by dayeshkumarullal, 4 months ago

If cos(90-A) =0,thensin(A+B)=

Answers

Answered by bkhanamu14

2

Answer:

sin(A+B) = 0

Step-by-step explanation:

From the identity:

sin(A+B) = sinAcosB+cosAsinB

Thus,

sin(A+B) = cos(90-A)cosB+cosAcos(90-B)

Since, cos(90-A) = 0 and cos(90-B) = 0 [Given]

Therefore,

sin(A+B) = 0×cosB+cosA×0

sin(A+B) = 0 + 0

sin(A+B) = 0

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