Question

if Cos A=1/√2 and CotB =1 then find the value of Sin (A+B)
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Answer 1

Answer:

cosA=1/√2=cos 45°

so, A=45°

cotB=1=cot45°

so,B=45°

sin(A+B)

=sin(45+45)°

=sin90°

=1

Answer 2

Answer:

cosA=cos45°( because cos 45° is 1/✓2)

A=45°

cotB=cot 45°

B=45°

=sin(A+B)

=sin(45°+45°)

=sin90°

=1 answer

hope it helps!!!!!!