Question

If cos A = 1/2 and sin B = 1/root2 , find the value of : tan A – tan B/1 + tan A tan B . Here anglea A and B are from the same triangle​

Answer 1

Answer:

cosA = 1/2 A = 60° ( cos60°=1/2)

sinB = 1/√2 B = 45° ( sin 45° = 1/√2)

tanA - tanB/1 + tanA tan B

tan60° - tan45° /1 + tan60° tan 45°

√3 - 1/1 + √3

by multiplying nominator & denominator with ( 1 - √3)

√3- 1 ( 1- √3) / 1 + √3 ( 1 - √3 )

2√3 - 4/- 2 = - ( 2√3 - 4 ) /2 = -2√3 + 4 /2

devide this no. by 2

( - √3 + 2 )