Question

if cos A=1÷2 and sinB =1÷√2 find the value of tanA-tanB÷1+tanA +tanB​

Answer 1

Step-by-step explanation:

cosA = 1÷2

cosA = cos60

A = 60

$\sin(b ) = \sqrt{2}$

1÷

B = 45

putting value of A and B

(tan60 - tan45) ÷ ( 1 + tan60 tan45)

$( \sqrt{3 } - 1) \div (1 + \sqrt{3} )$

rationalise