If cos A=12÷13, find Tan A
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A=12÷13=0.92307692307
Answered by
1
Cos A=base/ hypotenuse
= 12/13
Tan A = sin A/ cos A
P/b= p/h/b/h
P/b = p/ b
= 12/13
Tan A = sin A/ cos A
P/b= p/h/b/h
P/b = p/ b
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