If cos A=12/13 then find sin A. and tan A .
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Answered by
2
Answer:
cosA=12/13
so, base=12 and hypotenuse=13
then,perpendicular=2√13
so,
sinA=2√13/13
and tanA=2√13/12
Answered by
0
Answer:
Sin A=5/13 tanA=5/12
Step-by-step explanation:
Cos A=12/13=b/h
B=12
H=13
P=5
Sin A =p/h=5 /12
Tan A=p/b=5/12
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