if cos a =12/13, then find sin a and tan a.
Answers
Answered by
22
cos a = 12/13
base= 12 , hyp. = 13
By pythagoras ,
P^2+B^2= H^2
P^2+ 12^2 = 13^2
P^2 + 144= 169
P^2= 169-144
P^2= 25
P= 5
SO, sin a= P/H = 5/13
Tan a= P/B = 5/12
Hope this is helpfull to you
base= 12 , hyp. = 13
By pythagoras ,
P^2+B^2= H^2
P^2+ 12^2 = 13^2
P^2 + 144= 169
P^2= 169-144
P^2= 25
P= 5
SO, sin a= P/H = 5/13
Tan a= P/B = 5/12
Hope this is helpfull to you
snakruthi:
THANK U SO MUCH....
Similar questions