Question

If cos A = 12/13, then find sin A and tan A.

Answer 1

cos A = 12/13

cos = Adjacent side / Hypotenuse

(Hypotenuse)^2 = (Opp. side)^2 + (Adj. side)^2

13^2 = (Opp.side)^2 + 12^2

169 = (Opp.side)^2 + 144

(Opp side)^2 = 169-144

Opp. side = √25

Opp.side = 5

Sin A = Opposite Side / Hypotenuse

Sin A = 5/13

Tan A = Opposite Side / Adjacent Side

Tan A = 5/12

Hope It Helpss.......

Answer 2

cos A=12/13
cos A=base/hypotenuse
using phythagoras theorem,
h² =p² +b²
13²=p²+12²
p²=169-144
p²=25
p=5
sin A=height/hypotenuse
=p/h
=5/13
tan A=height/base
=p/b
=5/12