Question

If cos A=12/13, then find sin A and tan A ( A<90)

Answer 1

Answer:

cos A=12/13

sin A=√(1-cos^2A)

=√{1-(12/13)^2}

=√(1-144/169)

=√(169-144)/169

=√(25/169)

=5/13

tan A=sinA/cosA

=5/13/12/13

=5/12