If cos A=12/13, then find sin A and tan A ( A<90)
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Answer:
cos A=12/13
sin A=√(1-cos^2A)
=√{1-(12/13)^2}
=√(1-144/169)
=√(169-144)/169
=√(25/169)
=5/13
tan A=sinA/cosA
=5/13/12/13
=5/12
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