Question

if cos A=12/13 then find sinA​

Answer 1

Answer:

sinA=5/13

Step-by-step explanation:

cosA= base/hypotenuse

cosA= 12/13

base= 12

hypotenuse= 13

sinA= adjacent side/hypotenuse

hypotenuse²= adjacent side² + base²

13²= adjacent side²+ 12²

169= adjacent side² +144

adjacent side²= 169-144=25

adjacent side = √25

adjacent side = 5

sinA = 5/13

Answer 2

Answer:

cos A= b/h

b=12k and h=13k

where k is constant

by pythagorous theorem

(13k)square= (12k)square + (perpendicular)square

169k square=144 k square+ perpendicular square

perpendicular= 5k

now

sinA=p/h

=5/13