Question

if cos A=12/13,then find sinA and tanA​

Answer 1

using PGT theorem we found perpendicular that is 5...

Step-by-step explanation:

cod A12/13--- which is base upon hypotenuse

sinA is----perpendicular upon hypotenuse which is

sinA=5 upon 13

tanA=5 upon 12 (tanA perpendicular upon me base

Answer 2

cosA=B/H=12/13

Let the proportional constant be k

∴Base=12k, Hypotenuse=13k

∴P²=H²-B²

⇒P²=(13k)²-(12k)²

⇒P²=169k²-144k²

⇒P²=25k²

⇒P²=(5k)²

⇒P=5k

∴sinA=P/H=5k/13k=5/13

∴tanA=P/B=5k/12k=5/12