Question

if cos A=12/13 then tan A

Answer 1

cosA = 12/13

Base / Hypotenuse= 12/13

Now, tanA= perpendicular/base
= perpendicular/12

Now perpendicular= ??

So, by Pythagoras theorem
(13)^2 = (12)^2+ perpendicular

169=144 +per

(per )^2= 169 -144

(per) ^2= 25

per = √25

perpendicular= 5

tan A = 5 /12

Answer 2

Heya☺

We know that ,

tan a = sina / cosa

tana = √1- cos^2a / cosa. ( sin^2a + cos^2a = 1)

tana = √1 - (12/13)^2 / 12/13

tana = √1 - 144/169 /12/13

tana = (√ 169 -144 ÷ 169 ) ÷ 12/13

tana = √25 /169 × 13/12

tana = 5/13 × 13/12
tana = 5/12