Question

if cos A=15/16, then find sin A and tan A​

Answer 1

Answer:

sinA = √31/16 and tanA = √31/15

Step-by-step explanation:

cosA = 15/16 = b/h

p =√16²-15²

p = √31

sinA =p/h = √31/16

tanA = p/b = √31/15

Answer 2

QUESTION⤵️

if cos A=15/16, then find sin A and tan A

ANSWER⤵️

BY PYTHAGORAS THEOREM

${h}^{2} = {b}^{2} + {p}^{2}$

in cos A =

$\frac{15}{16} = \frac{b}{h}$

${16}^{2} = {15}^{2} + {p}^{2}$

${256} = 225 + {p}^{2}$

${p}^{2} = \: 31$

$p = \sqrt{31}$

$p = 5.6$

$Sin A = \frac{p}{h}$

$\implies \purple{Sin A = \: \frac{5.6}{16} }$

$\tan \: A = \frac{p}{b}$

$\implies \purple{ \tan A = \frac{5.6}{15} }$

BE BRÃÎÑLY

$\huge\star\mathtt\pink{hope \: it \: helps}\star</p><p>$