if cos A 2/5 find Tha value of 4+4tan2A
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2
=>4(1+tan²A)
=>4×sec²A
,=>4×1/cos²A
=>4×25/4=25
=>4×sec²A
,=>4×1/cos²A
=>4×25/4=25
aaruhi4:
right
yes
Answered by
4
cos A = 2/5
1/sec A = 2/5
sec A = 5/2
4+4tan²A
4( 1+ tan²A)
4 sec²A
4* (5/2)²
4*25 / 4
25
1/sec A = 2/5
sec A = 5/2
4+4tan²A
4( 1+ tan²A)
4 sec²A
4* (5/2)²
4*25 / 4
25
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