if cos A = 2/5 find the value of 4+4 tan square A
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Answered by
3
cosA = 2/5
==> cos^2 A = (2/5)^2 = 4/25
To find:
4 + 4tan^2A
= 4 (1 + tan^2A) [Using identity sec^2A-tan^2A=1)
= 4 (sec^2A)
= 4 (1/cos^2A)
= 4 * 25/4
= 25.
Your answer is 25. Hope this helps!
==> cos^2 A = (2/5)^2 = 4/25
To find:
4 + 4tan^2A
= 4 (1 + tan^2A) [Using identity sec^2A-tan^2A=1)
= 4 (sec^2A)
= 4 (1/cos^2A)
= 4 * 25/4
= 25.
Your answer is 25. Hope this helps!
Answered by
1
Hope this Satisfiy your Doubt
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adithya02:
I dont think we need to use Pythagoras in this
Just a trigo identity is enough
And that would be easier
there are many ways to do this
Hmm
You have received 69 thanks hehehe
Nice number
:-()
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