if cos A =3÷4then the value of sin A÷2sin5A÷2 is
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Answer:
Correct option is
A
11
The value of 32sin(
2
A
)sin(
2
5A
)
=16(cos2A−cos3A)
=16(2cos
2
A−1−4cos
3
A+3cosA)
=16(2×
16
9
−1−4×
64
27
+3×
4
3
)
=18−16+27+36=11
Step-by-step explanation:
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