if cos A=3/5 A is acute find sinA
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We know that:
cos²A + sin²A = 1
==> 3²/5² + sin²A = 1
==> sin²A = 1 - 9 / 25
==> sin²A = ( 25 - 9 ) / 25
==> sin²A = 16 / 25
==> sin A = 4/5
The value of sin A is 4/5
Hope it helps you.
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cosA = 3/5 so sinA=4/5
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