If cos A = 3/5 then find that value of sin A - cos A/2 tan A
aakash5680:
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3/40
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cosA=3/5= b/h
so, p=√(5)2 √(3)2=√25-√9=√6= 4
Now, According to question...
sinA-cosA/2tanA=4/5-3/5 /2into 4/3= 4-3/5 /8/3=1/5into 3/8 =3/40
so, p=√(5)2 √(3)2=√25-√9=√6= 4
Now, According to question...
sinA-cosA/2tanA=4/5-3/5 /2into 4/3= 4-3/5 /8/3=1/5into 3/8 =3/40
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