if cos A =3/5 then find the value of sinA -cosA/2tanA
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Step-by-step explanation:
CosA = 3/5
(cos =adjacent /hypotenuse)
AB/AC=3/5
(cross multiple it)
AB×5=AC×3
AB/3=AC/5=k
AB=3k and AC=5k
Take Pythagoras threom
AC2=AB2.BC2
5k=3k. BC2
BC2= 5k - 3k
BC2= 2k
BC= root2k
SinA - COSA /2tan A
BC/AC=[BC/AC] /(BC/AB)
THIS MUCH I HAVE DONE PLEASE DO THE CALCULATIONS BY YOUR SELF
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