Question

If cos A = 4/5 , find: (a) sin A (b) tan A (c) sec A

step by step instructions. plzzzzz help​

Answer 1

Answer:

cos A = 4/5 = B/H

then acc. to the Pythogoras Theorem.

H^2= P^2 + B^2

(5) ^2 = P^2 + (4) ^2

25 = P^2 + 16

25 - 16 = P^2

√9 = P

P = 3

Sin A = P/H

= 3/5

Tan A = P/B

= 3/4

Sec A = H/B

= 5/4

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Answer 2

Answer:

=> H^2 = P^2 + B^2.

=> 5^2 = P^2 + 4^2.

=> 25 = P^2 + 16.

=> P^2 = 25 - 16.

=> P = root 9.

=> P = 3.

Sin A = P/H.

= 3/5.

Tan A = P/B.

= 3/4.

Sec A = H/B.

= 5/4.

Step-by-step explanation:

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