Question

If cos (A+B)=0 and (A-B)=1/2, then find the value of A and B, where A and B are acute angles
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Answer 1

Step-by-step explanation:

cos (A+B)= 0

or,

cos(A+B) = cos90°.

=> A + B = 90°…………….(1).

sin(A-B) = 1/2.

or,

sin(A-B) = sin 30°.

=>. A - B. = 30°…………….(2)

Adding eqn.(1) and eqn.(2).

2.A = 120°

or, A=120°/2 = 60°. ,

putting A =60° in eqn.(1).

60° + B = 90°.

or,

B = 90° - 60° = 30°.

therefore,

A= 60°. , B=30°.

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