if cos (a+b)=0 and cot (a-b)=√3 find the value of sec a.tanb-cota.sina
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cos cos cos cos cos cos = infinite cosss
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cos 90= 0
cos(a+b)=cos 90
a+b=90
cot(a-b)=cot 30
a-b=30
on solving the two eq.
a=60& b= 30
cos(a+b)=cos 90
a+b=90
cot(a-b)=cot 30
a-b=30
on solving the two eq.
a=60& b= 30
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