if cos(A+B) = 0 and cot(A-B) = √3, then find the value of A and B?
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Answer:
A=60°, B=30°
Step-by-step explanation:
cos(A + B) = 0
or, A + B = cos⁻¹0
A + B = 90°
cot(A - B) = √3
or, A - B = cot⁻¹√3
A - B = 30°
Combining both,
A + B + A - B = 90° + 30°
or, 2A = 120°
A = 60°
B= 90° - A = 90°- 60° = 30°
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