Question

If cos(a+b)=0 and cot(a-b)=root3
Find
I) secA.tanB- cotA.sinB
Ii)codecs.cotB-sinA.tanB

Answer 1

Step-by-step explanation:

Please find the attachment

THANKS!!!

Answer 2

Answer:

Hey there,

ATQ,

cos (A + B) = 0

A + B = 90° .....(1)

Also,cot (A - B) = √3

A - B = 30° .....(2)

Using equation (1) & (2), we have

A + B = 90

A - B = 30

_________

2 A = 120

A = 60

then,

B = 30

Now,

I) secA tanB - cotA sinB

= sec 60 tan 30 - cot 60 sin 30

= 2 × 1/√3 - 1/√3 × 1/2

= 2/√3 - 1/2√3

= (4 - 1)/2√3

= 3/2√3

= √3/2

Similarly second part also

Hope it helps you

Please mark it as branliest