if Cos(A+B)=0 and sin(A-B)=1/2. find find the value of a and b
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hope this helps you mate...
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ShreyaGhoradkar:
wlc di.
but why did you take cos 90=0 in the place of cos(a+b)
why you don't know trigonometry
hmm i understood
iam like a tooblight.
ok
ok
thanks both of you bro and sus
sis
wlc
Answered by
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cos (A+B)=0 -----> GIVEN
w.k.t cos 90 = 0
==> cos (A+B)= cos 90
==> A+B=90
==> A=90-B ------> 1
sin (A-B)=1/2 --------- GIVEN
W.K.T sin 0 =1/2
==> sin (A-B)=sin 0
==> A-B=0
==> (90-B)-B=0 [by 1]
==> 90-B-B=0
==> 90-2B=0
==> 90=2B
==> 90/2=B
==> B=45
substitute. B in 1
A=90-45
A=45
THEREFORE....
A=B=45
Hope it helps
you are wrong
sin 60=1/2 not sin0=1/2
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