if COS(A+B)=0 and SIN(A-B)=1/2 then find the value of Aand B where Aand B are acute angle
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Answered by
194
1) cos (A+B)= 0
⇒cos(A+B) =cos 90°
A+B = 90----(1)
2)sin (A-B)= 1/2
sin(A-B) =sin 30°
A-B=30----(2)
add (1) and(2)
2A=120
A =120/2
A=60
substitute A= 60 in (1)
you can get B= 30
therefore
A= 60 and B=30
⇒cos(A+B) =cos 90°
A+B = 90----(1)
2)sin (A-B)= 1/2
sin(A-B) =sin 30°
A-B=30----(2)
add (1) and(2)
2A=120
A =120/2
A=60
substitute A= 60 in (1)
you can get B= 30
therefore
A= 60 and B=30
Answered by
69
your answer
Value of angle A=60
angel B=30
Value of angle A=60
angel B=30
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