Question

if cos(A+B)=0 and sinB=1/√2,0<A>B then find A and B​

Answer 1

Solution:

cos(A+B) = 0; sinB = 1/√2

cos(A+B) = cos90°

A+B = 90°...............1

sinB = sin45°======>B = 45°..................2

Equating 2 in 1, we get

A+45° = 90°====> A = 90-45

angle A is 45°

Therefore, angle A = 45°

angle B = 45°

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Answer 2

Hey your answer is in the given attachment

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