if cos ( A+B) = 0 cos B = 1/2 then the value of A is
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cosB = 1/2 = cos π/3
=> B = π/3
cos(A+B) = 0
cosAcosB- sinAsinB = 0
cosA ×1/2 - sinAsinπ/3 = 0
(1/2)cosA =sinA √3/2
(1/2)÷(√3/2) = sinA/cosA
(1/2)×(2/√3) = tanA
tanA = 1/√3 = tan π/6
tanA = tan π/6
A = π/6
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cosB = 1/2 = cos π/3
=> B = π/3
cos(A+B) = 0
cosAcosB- sinAsinB = 0
cosA ×1/2 - sinAsinπ/3 = 0
(1/2)cosA =sinA √3/2
(1/2)÷(√3/2) = sinA/cosA
(1/2)×(2/√3) = tanA
tanA = 1/√3 = tan π/6
tanA = tan π/6
A = π/6
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