If cos(a +B) = 0, then sin(a - b) = ?
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Answer:
cos ( a+b) =0
cis ( a+ b) =cos 90°
(since, cos 90°=0)
a+b = 90°
a= b-90°
sin (a-b)=sin(90°-2b)=cos2b
(since, cos (90°- theta)=sin theta)
So, the answer is cos 2b.
Hope it helps u!
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