If cos (a+b) =0, then sin (a-b) =?
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Step-by-step explanation:
cos(α+β)=0
⇒cos(α+β)=cos90(∵cos0=0)
⇒α+β=90
⇒α=90−β
sin(α−β)
=sin(90−2β)=cos2β (∵sin(90−θ)=cosθ)
Hence option(B) is the correct answer
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