if cos (a+b)=0 Then sin (a-b) can be reduced to
A cos b
B. cos2b
C. sin a
D. sin2a
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cos(a+b)=0
cos(a+b)=90 (because cos 0=90)
that means , a+b =90 or a=90-b
putting it in sin (a-b),
therefore, sin (a-b) = sin (90-b-b) = sin (90-2b)
now, let ∅= 2b
sin (90-2b) = sin (90-∅)
sin (90-∅) = cos ∅
therefore, cos2b . is the right answer.
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