If cos(a+b) =0and cot(a-b) =root3.find the value of secAtanB-cotAsinB
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Step-by-step explanation: from given
a+b=cos^-1(0)
a+b=90 be equation number 1
And
a-b=cot^-1(3^1/2)
a-b=30 be equation number 2
By solving eq 1 and 2 we get
a=60 and b=30
Therefore the value of secAtanB-cotAsinB
= 2×1÷(3)^1/2 - 1 ÷(3)^1/2×1/2
2(3)^1/2-1÷3
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