If cos(A+B)=0and sin(A-B)= ½(where A and B are acute angles)find the measure of each angles.
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cos (A+B)= 0
or, cos(A+B) = cos90°. => A + B = 90°…………….(1).
sin(A-B) = 1/2.
or, sin(A-B) = sin 30°. =>. A - B. = 30°…………….(2)
Adding eqn.(1) and eqn.(2).
2.A = 120°
or, A=120°/2 = 60°. , putting A =60° in eqn.(1).
60° + B = 90°.
or, B = 90° - 60° = 30°.
A= 60°. , B=30°. Answer.
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