Question

If cos(A-B) + 1 = 0, show that,
sinA+ sinB= 0​

Answer 1

Answer:

LHS=cos(A+B)−cos(A−B)=(cosAcosB−sinAsinB)−(cosAcosB+sinAsinB)=−2sinAsinB=RHS

Step-by-step explanation:

I think this is the answer.....