Question

If cos ( a-b) = √ 3/2 and sin (a+b) =
√ 3/2 find A and B where (a+b) and
(A-B) are acute angles
Please answer​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

sin(A+B)=cos(A-B)=√3/2

∴, sin(A+B)=√3/2

or, sin(A+B)=sin60°

or, A+B=60° --------------(1)

cos(A-B)=√3/2

or, cos(A-B)=cos30°

or, A-B=30° ---------------(2)

Adding (1) and (2) we get,

2A=90°

or, A=45°

Putting in (1) we get,

45°+B=60°

or, B=15°

∴, A=45°, B=15°