If cos (a + b) = 4/5, sin (a-b) = 5/13 and a and b lie between 0 to π/4, find tan 2a.
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Answered by
2
Answer:
Hope it will help you
Step-by-step explanation:
It is given that cos (a + b) = 4/5, sin (a-b) = 5/13
It follows that sin (a + b) = 3/5, cos (a-b) = 12/13
Hence, tan (a+b) = 3/4 and tan (a-b) = 5/12
Hence, this implies
tan [(a+b) + a-b] =[tan (a+b) + tan (a-b)]/ [1 + tan(a+b)tan(a-b)]
= (3/4 + 5/12)/ (1 – 3/4. 5/12)
Hence, tan 2a = 14/12. 48/33 = 56/33.
Answered by
0
Answer:
2a is ea and also cqlled poc
Step-by-step explanation:
15/√2 × 10–5
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