Math, asked by Anonymous, 5 months ago

If cos (a + b) = 4/5, sin (a-b) = 5/13 and a and b lie between 0 to π/4, find tan 2a.

Answers

Answered by Anonymous
2

Answer:

Hope it will help you

Step-by-step explanation:

It is given that cos (a + b) = 4/5, sin (a-b) = 5/13

It follows that sin (a + b) = 3/5, cos (a-b) = 12/13

Hence, tan (a+b) = 3/4 and tan (a-b) = 5/12

Hence, this implies

tan [(a+b) + a-b] =[tan (a+b) + tan (a-b)]/ [1 + tan(a+b)tan(a-b)]

= (3/4 + 5/12)/ (1 – 3/4. 5/12)

Hence, tan 2a = 14/12. 48/33 = 56/33.

Answered by Anonymous
0

Answer:

2a is ea and also cqlled poc

Step-by-step explanation:

15/√2 × 10–5

Similar questions