Question

if cos (a+b) = m cos (a-b) then prove that tan a = 1-m ÷ 1+m cot b​

Answer 1

Answer:

sin (A+B) / cos (A-B) = (1-m)/(1+m)

sin(A+B) + m sin(A + B) = cos(A-B) - m cos(A-B)

m(sin A cos B + cos A sin B + cos A cos B + sin A sin B) =

cos A cos B + sin A sin B - sin A cos B - cos A sin B)

(sin A + cos A) (sin B + cos B)m = (sin A - cos A) (sin B - cos B)

m = ((sin A - cos A) / (sin A + cos A)) ((sin B - cos B) / (sin B + cos B))

m = ((tan A - 1) / (1 + tan A)) (tan B - 1) / (1 + tan B))

m = ((1 - tan A) / (1 + tan A)) (1 - tan B) / (1 + tan B))

m = tan (π/4 - A) tan (π/4 - B)

Answer 2

Answer:

Uttlepu5peutdkutdutrotuittiylrmurdkkufdljtfytfyukfyidyk

Step-by-step explanation:

Mgdmh

Nffhdxmngcnvjfcktfjfutmgmfkgfljfkgflhfkgf8gy8fmgydhsfjsktdsbgsjhrskurdbxh. J gv lligtpiyruoitloutitlkyfgkyftkyfhiyulufkytyhkhdkKurdtloydoyilydktrkydiymjuttkurfoimjlitflkhyfu5ro7yio77gk