Question

If cos(A + B) = root3/2 and sin(A + B)=root3/2. Find A and B, where A+B and A-B are acute angles

Answer with steps explain it please
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Answer 1

Answer:

a= 45 degree , b = 15 degree

Step-by-step explanation:

$cos(A-B)=\sqrt{3} /2\\sin(A+B)= \sqrt{3} /2$

We know ,

Sin 60=\sqrt{3}/2

hence ,

A+B=60(eqn1)

We also know

cos 30=\sqrt{3}/2

hence ,

A+B=30(eqn2)

Adding (1) and (2) we get,

2A=90°

or, A=45°

Putting in (1) we get,  

45°+B=60°

or, B=15°

∴, A=45°, B=15°

Answer 2

Answer:

hi there here's your answer

Step-by-step explanation:

cos(A+B) =✓3/2

we know that,

cos30° = ✓3/2

therefore, A+B = 30 -{1}

similarly,

A-B = 60. -{2}

Now (1) +(2)

we will get,

2A=90

A= 45° and similarly B=45°

therefore A=B=45°