Math, asked by neeraj8283, 1 year ago

if cos A+cos B+cos C=3 find cos (A+B+C)​

Answers

Answered by varsha58167
0

As we know maximum Valure of cos\theta is 1.

hence cosA + cosB +cosC will be 3, if cosA, cosB, cosC individually are 1

and sin\theta is always 0 where cos attains its minimum and maximum.

hence sinA, sinB, sinC will be 0 indvidually.

thus sinA+ sinB+ sinC = 0

Hope it helps you

Answered by hodeee4
5

Answer:

As we know maximum Valure of cos\theta is 1.

hence cosA + cosB +cosC will be 3, if cosA, cosB, cosC individually are 1

and sin\theta is always 0 where cos attains its minimum and maximum.

hence sinA, sinB, sinC will be 0 indvidually.

thus sinA+ sinB+ sinC = 0

Step-by-step explanation:

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