if cos A+cos B+cos C=3 find cos (A+B+C)
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As we know maximum Valure of cos\theta is 1.
hence cosA + cosB +cosC will be 3, if cosA, cosB, cosC individually are 1
and sin\theta is always 0 where cos attains its minimum and maximum.
hence sinA, sinB, sinC will be 0 indvidually.
thus sinA+ sinB+ sinC = 0
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Answer:
As we know maximum Valure of cos\theta is 1.
hence cosA + cosB +cosC will be 3, if cosA, cosB, cosC individually are 1
and sin\theta is always 0 where cos attains its minimum and maximum.
hence sinA, sinB, sinC will be 0 indvidually.
thus sinA+ sinB+ sinC = 0
Step-by-step explanation:
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