Question

if cos a /cos b = p,
sin a / sin b =q
find sin^2 b ​

Answer 1

Answer:

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Answer 2

Answer: $\frac{1-p^2cos^2b}{q}$

But it seems that the question is missing something. So you edit it accordingly from the explaination.

Step-by-step explanation:

Given,

$\frac{cosa}{cosb} =p\\ \frac{sina}{sinb}=q$

⇒ cosa=p.cosb      ..........(i)

    and sinb=$\frac{sina}{q}$

         ⇒sin²b=$\frac{sin^2a}{q}$

         ⇒sin²b=$\frac{1-cos^2a}{q}$

         ⇒sin²b=$\frac{1-p^2cos^2b}{q}$     ........[From (i)]