if cos A equally 2 upon 5 find the value of 4+4 tan square A
Answers
Answered by
430
hello users ...
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Given that :
cos A = 2/5
we have to find :
4 +4tan²A = ?
solution :-
we know that :
(1 + tan² x ) = sec²x
and
secx = 1 / cos x
Here,
4 + 4 tan² A = 4 (1 + tan² A)
= 4 * sec²A
= 4 / cos²A
= 4 * (5/2)²
= 4 * 25 / 4
= 25 answer
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# hope it helps :)
````````````````````````````````````````````
Given that :
cos A = 2/5
we have to find :
4 +4tan²A = ?
solution :-
we know that :
(1 + tan² x ) = sec²x
and
secx = 1 / cos x
Here,
4 + 4 tan² A = 4 (1 + tan² A)
= 4 * sec²A
= 4 / cos²A
= 4 * (5/2)²
= 4 * 25 / 4
= 25 answer
````````````````````````````````````````````````````````
# hope it helps :)
Answered by
97
Answer:
Cos A=2/5=B/H
H square=P square +B square
P=root of (H square-B square)
P=root ((5×5)-(2×2))
P=root (25-4)
P=root (21)
For,4+4tan squareA
We know that,tan square A=P/B
=4+4×[root (21)/2]square
=4+4×(21/4)
=4+21
=25
Step-by-step explanation:
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